Your second problem is one in Special Relativity. You should start by looking in your text at the definition of simultaneity. If two events happen at the same time, as the marshal thinks is the case, it just means that light from the two events reached him at the same time. Knowing the relative positions of everyone and the speed of the marshal you have to figure out the distance that the light from each shooter traveled to reach the train and then decide who fired first based on how long the light took to reach the marshal from each.
It would also be helpful to draw some space-time diagrams for each of the three observers so you can see what's going on from each's point of view.
And, finally, the Lorentz equations will tell you exactly how much time dilates for each observer here.
And some thoughts on question 4. I'm sure your text book tells you how relativistic mass is related to velocity and you know how to relate mass to kinetic energy. So it seems to me that the same problem in a different light would be to find the speed of a particle when its relativistic mass is twice its rest mass.
figured out problems three and four... the following is what three and four will look like when solved...
Question #3 An observer looks at a source through a grating having 1000 slits per cm. If the wavelength is 550nm, how many images of the source can be seen? (Hint: For what order would theta be + or - 90 degrees)
Answer: d = grating spacing deviation angle = 30 degs λ = wave length of light n = spectral order N = no of lines / cm = 1000 N= 1/d or d = 1/N = 1/103 cm = 10-3 cm = 10 -5 m nλ = d Sin λ = 550 nm = 550 x 10 -9 m. Maximum number of images will be seen for greatest angle of deviation i.e. = + or - 90 degs hence Sin = + or - 1 therefore the order numbers for the visible spectrum for the grating are limited to n < = d / λ = 10 -5 / 550 x 10 -9 = 18.2 hence 18 complete orders will be observed, or 36 images;18 on each side of central maximum (x-1)mo c2 = mo c2 {1 / (1 - v2 / c2) - 0.5} - 1 = 1 1 / (1 - v2 / c2) - 0.5 = 2 1 - v2 / c2 = 1/4 v = 0.866c
Question #4 What is the speed of a particle A. whose kinetic energy is equal to twice its rest energy and B. whose total energy is equal to twice its rest energy?